Patchwork [01/10] x86/efi: Mark can_free_region() as an __init function

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Submitter Ard Biesheuvel
Date Feb. 2, 2019, 9:41 a.m.
Message ID <20190202094119.13230-2-ard.biesheuvel@linaro.org>
Download mbox | patch
Permalink /patch/716589/
State New
Headers show

Comments

Ard Biesheuvel - Feb. 2, 2019, 9:41 a.m.
From: Sai Praneeth Prakhya <sai.praneeth.prakhya@intel.com>

can_free_region() is called only once during _boot_ by
efi_reserve_boot_services(). Hence, mark it as __init function.

Signed-off-by: Sai Praneeth Prakhya <sai.praneeth.prakhya@intel.com>
Signed-off-by: Ard Biesheuvel <ard.biesheuvel@linaro.org>
---
 arch/x86/platform/efi/quirks.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

Patch

diff --git a/arch/x86/platform/efi/quirks.c b/arch/x86/platform/efi/quirks.c
index 17456a1d3f04..9ce85e605052 100644
--- a/arch/x86/platform/efi/quirks.c
+++ b/arch/x86/platform/efi/quirks.c
@@ -304,7 +304,7 @@  void __init efi_arch_mem_reserve(phys_addr_t addr, u64 size)
  * - Not within any part of the kernel
  * - Not the BIOS reserved area (E820_TYPE_RESERVED, E820_TYPE_NVS, etc)
  */
-static bool can_free_region(u64 start, u64 size)
+static __init bool can_free_region(u64 start, u64 size)
 {
 	if (start + size > __pa_symbol(_text) && start <= __pa_symbol(_end))
 		return false;